What are the vertices of triangle A'B'C' produced by (x, y) -> (x+5, y-2)?

The vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

As the rule of translation is given by

Translation: (x, y)  →  (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0)  → (x+5, y-2)  ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2)  →  (x+5, y-2)  ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2)  ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation: