The average score of a sample of 87 senior business majors at UTC who took the Graduate Management Admission Test was 510 with a standard deviation of sample 36. Provide a 98% confidence interval for the mean of the population.

500.85 to 519.15

Step-by-step explanation:

The computation is shown below;

The z value for the 98% confidence interval is 2.33

Now the margin of error is

= (z × standard deviation) ÷ √n

= (2.33 × 36) ÷ √87

= (83.88 ) ÷ √87

= 83.88 ÷ 9.327379

= 8.99

= 9

Now The confidence interval mean is

= (510 - 9) (510 +9)

= (501) ; (519)

answer: 0.1,0.85

step-by-step explanation:

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step-by-step explanation:

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look above, and leave your comments down below, and don't for get a five stars and a and brainliest xd

sorry for the stars in the middle of words its because it wouldn't let me submit. xd