What is the smallest initial velocity that is required to throw a stone 49 feet up on top of a silo?

the smallest initial velocity that is required to throw the stone is 56 ft/s

Step-by-step explanation:

We know that;

u = initial velocity  

v = final velocity  = 0

a = acceleration  = -g = -32,

s = distance travelled  = 49 feet

V² - u² = 2aS

we substitute

0² - u² = 2 × -32 × 49

0 - u² = -3136

u² = 3136

u = √3136

u = 56 ft/s

Therefore the smallest initial velocity that is required to throw the stone is 56 ft/s

99

step-by-step explanation:

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.