2x-y and 7y= -7 +3x solve by substitution

x = -7/11, y = -14/11

Step-by-step explanation:

2x = y (1)

7y = -7+3x (2)

from (1)

2x = y

y = 2x (3)

substitute (3) into (2)

7y = -7+3x

7(2x) = -7+3x

14x = -7+3x

14x-3x = -7

11x = -7

x = -7/11

substitute x = -7/11 into (3)

y = 2x

y = 2(-7/11)

y = -14/11

x = -7/11, y = -14/11

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9