Solve 3cosx-1,0<=x<=pi/2

E(-9)≈3.4936

Step-by-step explanation:

Calculate the arc length of the following curve from x = 0 to x = π/2:

y(x) = -1 + 3 cos(x)

Hint: | The definition of arc length in Cartesian coordinates is s = integral_(x_0)^(x_1) sqrt(1 + y'(x)^2) dx.

Apply the definition of arc length to y(x) = -1 + 3 cos(x) for 0<x<π/2:

s = integral_0^(π/2) sqrt(1 + (d/dx(-1 + 3 cos(x)))^2) dx

Hint: | What is d/dx(-1 + 3 cos(x))?

Compute the derivative d/dx(-1 + 3 cos(x)):

= integral_0^(π/2) sqrt(1 + (-3 sin(x))^2) dx

Hint: | Can the integrand be simplified?

Simplify sqrt(1 + (-3 sin(x))^2):

= integral_0^(π/2) sqrt(1 + 9 sin^2(x)) dx

Hint: | Can this integral be computed?

Compute the definite integral:

E(-9)≈3.4936

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

step-by-step explanation: