Identify the errors made in finding the inverse of y = x2 + 12x.
x= y2 + 12x
y2 = x - 12x
y2=-11x
y=-11x, for x > 0
Describe the three errors?

Step-by-step explanation:

y = x2 + 12x.

x= y2 + 12x           would also be 12 y

y2 = x - 12x               would be -x

y2=-11x  

y=, for x > 0    negative  square root not possible

Describe the three errors?

12 servings. 4 times 3= 12

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: