Divide quadratics by linear expressions (with remainders) Divide the polynomials.
Your answer should be in the form p(x) +
where p is a polynomial and k is an integer.
3
37
22 + 4
3
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x + 3 +

Step-by-step explanation:

Divide using Synthetic division

dividing by ( x - 3)

Using 0 to represent the x- term

3 |  1  0   4

     ↓ 3    9

        +     +

   ------------------

     1   3    13 ← remainder

Thus

= x + 3 +

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?