Right triangle FGH has midsegments of 15,36, and 39 centimeters given that area of a triangle is represented by the formula A=1/2bh determine the area of triangle FGH A.180cm2
B.1080cm2
C.1170cm2
D.2160cm2

Step-by-step explanation:

according to the midsegment theorem, a midsegment of a triangle is parallel to a side of a triangle and its length is 1/2 length of the side.

1/2FG= 15, SO FG=30,

1/2 GH=36 SO GH=72

AREA = 1/2(72*30)=1080 CM^2

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.