Jeanna is making holiday cupcakes for her family. She typically makes 2 dozen red velvet and 3 dozen gingerbread spice cake. Since everyone is staying home for the holiday, she needs to increase this standard amount by 3 to have enough to send to family and friends far and wide. How many dozens of cupcakes will Jeanna need to make?

15 dozens of cakes

Step-by-step explanation:

It is given that Jeanna is making cupcakes for her family and she normally makes 2 dozens of red velvet cakes and 3 dozens of gingerbread spice cakes. But as everybody is staying at home, Jeanna wants to increase the standard amount by 3 for enough cakes.

So,

2 dozens of velvet cakes, i.e.

2 x 12 = 24 red velvet cakes

Increasing this amount by 3 times will give us 24 x 3 = 72 red velvet cakes.

Similarly,

3 dozens of gingerbread spice cakes, i.e.

3 x 12 = 36 gingerbread spice cakes

Increasing this amount by 3 times will give us 36 x 3 = 108 gingerbread spice cakes.

Therefore the total number of cakes is = 72 + 108

                                                                 = 180 cakes.

We know 1 dozen = 12

Therefore dividing 180 cakes by 12, we get

= 15 dozen cakes.

Therefore, now Jeanna will have to make 15 dozens of cupcakes for all.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.