Who is your favorite College Football Team & College Football Player ? Tell why and name six (6) facts about the team.

Use complete sentences.

. J. Watt

American football defensive end

lyrics

Panalangin ko sa habang buhay

Makapiling ka, makasama ka

'Yan ang panalangin ko

At hindi papayag ang pusong ito

Mawala ka sa 'king piling

Mahal ko iyong dinggin

At wala ng iba pang mas mahalaga

Sa tamis na dulot ng pag-ibig nating dalawa

Sana naman makikinig ka

Kapag aking sasabihing

Minamahal kita

Panalangin...

Panalangin ko sa habang buhay

Makapiling ka, makasama ka

'Yan ang panalangin ko

At hindi papayag ang pusong ito

Mawala ka sa 'king piling

Mahal ko iyong dinggin

At wala ng iba pang mas mahalaga

Sa tamis na dulot ng pag-ibig nating dalawa

Sana naman makikinig ka

Kapag aking sasabihing

Minamahal kita

Panalangin ko sa habang buhay

Makapiling ka, makasama ka

'Yan ang panalangin ko

At hindi papayag ang pusong ito

Mawala ka sa 'king piling

Mahal ko iyong dinggin

Panalangin ko sa habang buhay

Makapiling ka, makasama ka

'Yan ang panalangin ko

At hindi papayag ang pusong ito

Mawala ka sa 'king piling

Mahal ko iyong dinggin

Panalangin...

Panalangin...

a.)the line for function b is steeper

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.