Please help. 40 points + brainliest (***NOTICE: Bots/trolls seeking points will be reported***)

1. Solve for q:

√3q + 2 = √5

2. solve for d:

4d + 1 = √3

3. Solve for m:

m/√3 - 11 = 4

1) q = (sq rt 15 - 2) / 3

2) d = (sq rt 3 - 1) / 4

3) m = 15 * sq rt 3

Step-by-step explanation:

1.√3q + 2 = √5

we bring to the power of 2 each element

(√3q)^2+2^2=√5^2

3q+4=5

3q=4-5

q=1/3

2.

4d+1=√3

we do the same thing

16d^2+1=3

16d^2=2

d^2=2/16

d^2=1/8

d=√1/√8

3.

m/√3 -11=4

first we rationalise by multiplying the first fraction with √3

m√3 /3-11=4

now we can bring to the power of 2

3m^2/9-121=16

3m^2/9=137

m^2/3=137

m^2=411

m=√411

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240