What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment? y = One-thirdx
y = One-thirdx – 2
y = 3x
y = 3x − 8

Complete Question:

The given line segment has a midpoint at (3, 1). On a coordinate plane, a line goes through (2, 4), (3, 1), and (4, -2).

What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?

Step-by-step explanation:

From the question, we understand that the line goes through

First, we calculate the slope of the above points

Where

Also; from the question, we understand that the line segment is perpendicular to the above points.

This slope (m2) of the line segment is calculated as:

Substitute -3 for m

Lastly, we calculate the equation of the line using:

The line segment has a midpoint at (3, 1)

So:

Open bracket

Add 1 to both sides

Hence, the equation of the line segment is:

sites:

lolololkzaxio2ier286udeg