Solve the triangle with the law of sines

see below

Step-by-step explanation:

We can use the law of sines

sin 80             sin B

=

31                       14

Using cross products

14 sin 80 = 31 sin B

14/31  sin 80 = sin B

.984807753 = sin B

Taking the inverse sin of each side

sin ^ -1 ( .444751888) =  B

26.41 = B

The sum of the angles of a triangle is 180

A+B+C = 180

80 + 26.41 + C =180

106.41 + C = 180

C = 73.59

We can use the law of sines to find c

sin 80             sin 73.59

=

31                       c

c sin 80 = 31 sin 73.59

c =  31 sin 73.59 / sin 80

c = 30.20

AB = 30.20

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.