On a given day, the proportion of workers from Company B who purchase a coffee from the company cafeteria is 0.62 and the proportion of workers from Company C who purchase a coffee from the company cafeteria is 0.71. A random sample of 40 workers was selected from Company B and another random sample of 40 workers was selected from Company C. The proportion of workers from Company B who purchased coffee was

The proportion of workers from Company who purchased coffee was:

= 0.31

Step-by-step explanation:

Proportion of workers from Company B who purchase a coffee = 0.62

Proportion of workers from Company C who purchase a coffee = 0.71

Random sample of workers selected from Company B = 40

Random sample of workers selected from Company C = 40

Number of workers from Company B who purchased coffee  = 25 (0.62 * 40)

Number of workers from Company C who purchased coffee = 28 (0.71 * 40)

The proportion of workers from Company B who purchased coffee overall = 25/80 = 0.3125

The proportion of workers from Company C who purchased coffee overall = 28/80 = 0.35

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation: