What are the xintercepts of the graph of the function below?
y=x^2+4x-32

To find the x intercepts of a given equation, simply substitute in y=0

x^2+4x-32=0

Solve via sum and product (what two numbers add up to +4 and what two numbers multiply to give -32)

x^2+8x-4x-32=0

x(x+8)-4(x+8)=0

(x-4)(x+8)=0

(x-4)=0 and (x+8)=0

So, the two x intercepts are 4 and -8, which is option b