The Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse by the formula a? + b2 = -2
If a is a rational number and b is a rational number, why could c be an irrational number?

For the value of hypotenuse can be irrational, sum of squares of other two legs might be imperfect square number.

Step-by-step explanation:

We all know, the Pythagorean theorem can be stated as follows:

The sum of squares of two legs of a right angled triangle is equal to the square of the hypotenuse.

i.e.

Where, is the hypotenuse and are the two other legs of the right angled triangle.

Given that:

and are rational numbers.

To find:

Situation for which is irrational.

Square of a rational number is always rational.

So, both will be rational.

And sum of squares of two rational numbers will also be rational.

Therefore, will also be rational.

and

For the value of can be irrational, sum of squares of other two legs might be imperfect square number.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.