If sin0=4/5, then cos0 =

If sin(theta) = 4/5, what is the value of cos(theta) in quadrant 1?

sin^2(theta) + cos^2(theta) = 1

(4/5)^2 + cos^2(theta) = 1

16/25 + cos^2(theta) = 1

cos^2(theta) = 1 - 16/25

cos^2(theta) = 25/25 - 16/25

cos^2(theta) = (25 - 16)25

cos^2(theta) = 9/25

cos(theta) = sqrt(9/25) ... we are in quadrant I, so cos(theta) > 0

cos(theta) = 3/5

Step-by-step explanation:

Hope it is helpful...

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

may i see the picture? it would a lot, xox