Dec 23, 8:45:08 PM Find three consecutive POSITIVE ODD integers such that when you multiply the first
and third the result is nine less than six times the second integer.

3, 5, 7

Step-by-step explanation:

Let the first of the three positive consecutive odd numbers be .

Now, the second odd number =

And, the third odd number =

As per question statement, the multiplication of the first and third odd number is 9 lesser than the 6 times the second integer.

Writing the equation, we get:

As, we got a quadratic equation, so we have two solutions here.

One is positive integer and other one is negative.

So, solution is

First number is 3.

Second number is 3 + 2 = 5

Third number is 5 + 2 = 7

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

answer: 1 + 1 = 11

step-by-step explanation: