The terminal side of Ø is in quadrant II and sin ø = 5/13 What is cos ø? A. 5/12
B. -12/13
C. -5/12
D. 12/13

Step-by-step explanation:

In Quadrant II, cosine is negative.

We know that sin²x + cos²x = 1, so:

cosx = sqrt[1 - sin²x]

= sqrt[1 - (5/13)²]

= sqrt(144/169)

= -12/13 (since cosx is negative here)

The answer is -12/13. (B)

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: