Iran surveyed a random sample of students in her school district, and she found these statistics: \begin{aligned} &P(\text{rides bike to school})=0.14 &P(\text{has crossing guard})=0.48 &P(\text{rides bike and crossing guard})=0.12 \end{aligned}

P(rides bike to school)=0.14
P(has crossing guard)=0.48
P(rides bike and crossing guard)=0.12

Find the probability that a student rides a bike to school, given that the student's school has a crossing guard.
P\left( \text{rides bike }| \text{ crossing guard} \right)=P(rides bike ∣ crossing guard)=P, left parenthesis, start text, r, i, d, e, s, space, b, i, k, e, space, end text, vertical bar, start text, space, c, r, o, s, s, i, n, g, space, g, u, a, r, d, end text, right parenthesis, equals