A ball is dropped from a height of 50 feet. The function f(x) = 50(0.6)x gives the height in feet of feet of each bounce, where x is the bounce number. What is the height of the third bounce to the nearest tenth of a foot?

The height of the third bounce is 10.8 feet

Step-by-step explanation:

Let us solve the question

∵ A ball is dropped from a height of 50 feet

∵ The function f(x) = 50 gives the height in feet of each bounce

∵ x is the bounce number

∵ We need to find the height of the third bounce

∴ x = 3

→ Substitute x by 3 in the function above

∵ f(3) = 50(0.6)³

∴ f(3) = 50(0.126)

∴ f(3) = 10.8

∴ The height of the third bounce is 10.8 feet

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204