Can someone just solve the problem please? it has to be an inequality in the equation

(A) Let a represent the number of hours Cassie needs to work

(B) The inequality is 10 × a + 30 ≥ 140

(C) a ≥ 11

(D) Cassie needs to work babysitting for her neighbor for at least 11 hours to be able to buy the graphing calculator

Step-by-step explanation:

The least amount Cassie needs for the graphing calculator = $140

The amount Cassey currently have saved = $30

The amount her neighbor offers for her to babysit = $10 per hour

(A) The definition of the variable is given as a = The number of hours Cassie needs to work

(B) The inequality that defines the situation is 10 × a + 30 ≥ 140

(C) Solving the inequality gives;

10 × a + 30 ≥ 140

10 × a  ≥ 140 - 30

∴10 × a  ≥ 110

a ≥ 110/10

∴ a ≥ 11

Which gives;

The number of hours Cassie needs to work = a ≥ 11 hours

(D) The solution means that Cassie needs to babysit for her neighbor for at least 11 hours to be able to buy the graphing calculator.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)