The ratio of the number of left-handed batters in a team to the number of right -handed batters was 5 : 8 there were 45 left-handed batters . \
a) how many right-handed batters were there?

b) find the ratio of the number of left- handed batters to the total number of batters express youe=r answer in simplest form

a) 72 right-handed batters

b) 5:13

Step-by-step explanation:

This is the answer because:

1) For problem a, we can see that 5 x 9 = 45. In order to balance the ratio, we also have to mulitply the 8 with a 9:

8 x 9 = 72

Therefore, the answer is 72 right-handed batters.

2) For b, there are two ways to do it. Sine we know that there are 5 left-handed batters, we just add 5 + 8 = 13. Therefore, the simplest form of the ratio is 5:13. Another we can do it is by adding 45 + 72 = 117 (total batters). Then, 45 of them are left-handed batters which means the ratio is 45:117 = 5:13.

Therefore, the answer is 5:13.

Hope this helps! :D

32

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%