You are given parallelogram ABCD and side AB is congruent to side DC. Prove segment AM is congruent to segment CM.
*Upload a picture of your markings along with your proof

Given triangle RPQ is isosceles and C is the midpoint of line RQ.
Prove that angle RPC is congruent to angle QPC.
*Upload a picture of your markings along with your proof

ABM=CDM-DMC=BAM alternate interior angles

AMB=CMD verticle angles

triangle AMB=CMD by ASA

A=c CPTC

ABD=BDC, BAC=ACD, ADB=DBC by CPCTC

AM=CM def of a Parallelogram

2.

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RPQ is an isosceles triangle. C is the midpoint of line RQ- Given

RPC=QPC- construction

PC=PC reflective property

∠

RPC= QPC- SAS

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!