Given that 6 > –2, which statements are true? Check all that apply. (2)(6) > (–2)(2)

StartFraction 6 over 2 EndFraction less-than StartFraction negative 2 over 2 EndFraction

(–2)(6) > (–2)(–2)

StartFraction 6 over negative 2 EndFraction less-than StartFraction negative 2 over negative 2 EndFraction

(2)(6) < (–2)(2)

StartFraction 6 over 2 EndFraction less-than StartFraction negative 2 over 2 EndFraction

75

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

step-by-step explanation:

no solution.