The quadratic function d=−5x2+77 models a sled's distance, in feet, from the bottom of a hill x seconds after the sled starts moving down the hill. When does the sled get to the bottom of the hill?

after 3.92 seconds

Step-by-step explanation:

Given the quadratic equation that models the sledge distance expressed as;

d = -5x^2 + 77

The sled get to the bottom of the hill at when d  = 0. Substitute into the equation given;

0 = -5x^2 + 77

5x^2 = 77

x^2 = 77/5

x^2 = 15.4

x = √15.4

x = 3.92

Hence the sled get to the bottom of the hill after 3.92 seconds

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.