Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE =2x, BE = y +10, CE =x+2 and DE = 4y - 8. Find x.
A. 4
B. 6
C. 2
D. 8

Step-by-step explanation:

Given parallelogram ABCD with diagonals AC and BD intersect at point E, then;

AE = CE and BE = DE

Given;

AE =2x, BE = y +10, CE =x+2 and  DE = 4y - 8.

Recall that AE = CE

2x = x+2

2x - x = 2

x = 2

Hence the value of x is 2

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes