Find the distance from a vector (2; 3; 1)T to the subspace spanned by the vectors (1; 2; 3)T , (1; 3; 1)T . Note, that I am only asking to nd the distance to the subspace, not the orthogonal projection.

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!

yep b and c r the correct got it! : )

you did the answer gesesgsesegsge

answer-

the equation that models this pattern is

solution-

a researcher placed a petri dish with 32,000 bacterial cells. one hour after being placed in the vacuum chamber, the number of cells in the petri dish had halved. another hour later, the number of cells had again halved.

this can be represented as exponential decreasing function,

where,

putting the values,

y-intercept means, where x=0, so

the coordinate of this poin will be (0, 32000)

this means when x=0 or at the starting of the research, the number of bacteria cells was 32000.

after 3 hours, number of bacteria cells will be,

the   coordinate of this point will be (3, 4000)