Find an equation of a line parallel to y=-3x +4 that goes through the point (-2,5).

y=-3x-1

Step-by-step explanation:

Parallel lines have the same slope. Since the original line has a slope of -3, the line that is parallel to it also has a slope of -3.

1. Use point-slope: y-y1=m(x-x1). M represents slope and x1 and y1 represent the x and y values of the ordered pair.

y-5=-3(x+2)

2. Simplify

First, distribute -3 to x and +2

Rewrite the equation as y-5=-3x-6

Add 5 to both sides

y=-3x-1

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons