Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 11 people took the trip. She was able to purchase coach tickets for $240 and first class tickets for $1080. She used her total budget for airfare for the trip, which was $4320. How many first class tickets did she buy? How many coach tickets did she buy?

You can set up a system of equations for this problem. Let x = number of coach tickets and y = number of first-class tickets. Then:

330x + 1220y = 12730    (cost of coach tickets plus cost of first-class tickets is total budget)

x + y = 17    (number of coach tickets plus the number of first-class tickets is the total number of people)

Solve the second equation for y to get y = 17 - x, then plug that into the first equation and solve for x:

330x + 1220(17 - x) = 12730

330x + 20740 - 1220x = 12730

-890x + 20740 = 12730

-890x = -8010

x = 9

Sarah bought x = 9 coach tickets. Put that into the second equation and solve for y:

9 + y = 17

y = 8

Sarah bought y = 8 first-class tickets.

Hope this helps!! :D

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz