Find a · b, given a = 12(cos pi/3 + i sin(pi/3)), b = 3 (cos(pi/4)+ i sin(pi/4)) Show 3 decimal places.
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a = 12 (cos(π/3) + i sin(π/3))

b = 3 (cos(π/4) + i sin(π/4))

a • b = 36 (cos(π/3) cos(π/4) + i cos(π/3) sin(π/4) + i cos(π/4) sin(π/3) + i ² sin(π/3) sin(π/4))

… = 36 (cos(π/3 + π/4) + i sin(π/3 + π/4))

… = 36 (cos(7π/12) + i sin(7π/12))

… ≈ -9.32 + i 34.8

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: