Ravi and Grace know there is a 1/3 chance that two random players will tie each other in a given attempt at the game rock-paper-scissors. They plan to play 6 attempts against each other. Assume that the results of
subsequent attempts are independent, and let T represent the number of attempts where they tie,
Which of the following would find PT = 2)?

(6) (1/3)^2 (2/3)^4

(2)

Step-by-step explanation: Each arrangement has a probability (1/3)^2 (2/3)^4 so our final answer we multiply this probability by the number of possible arrangements

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

15% chance.

step-by-step explanation:

3/10 times, the 5 year old will get a tablet. 5/10 times, the 13 yer old will get a tablet. multiply both fractions to get 15/100 times, both would have a tablet.