12, 20, 15, 18, 12, 18, 10, 14
What would happen if I took out 12 from the set?

Answer

If you took out 12 from the set...

The mean would be about 15.29.

The median would be 15.

The mode would be 18.

The mean will increase.

The median will increase.

There will be a mode.

Explanation - Before Taking Out 12

If you still had 12 in the set, the numbers in the set would be this.

10, 12, 12, 14, 15, 18, 18, 20

The mean would be about 14.88. The mean is the sum of the numbers in a set divided by the number of numbers in the set.

10+12+12+14+15+18+18+20 = 119.

119÷8 = 14.875.

This is about 14.88.

The median would be 14.5.

The median is the middle number in the set.

The middle number in the set is 14 and 15.

So you find the mean of 14 and 15 (because there is no middle number, you find the average of the two middle numbers).

14+15 = 29

29/2 = 14.5

The mode would be 12 and 18. The most frequent numbers are 12 and 18. They both appear two times.

The range is 10.

The range is the smallest number subtracted from the largest number.

The largest number is 20 and the smallest number is 10.

20-10 = 10.

Explanation - After Taking out 12

If you took out 12 from the set, the numbers in the set would be this.

10, 12, 14, 15, 18, 18, 20

The mean would be the sum of these numbers divided by 7.

10+12+14+15+18+18+20 = 107.

107÷7 = 15.28571429.

So it would be about 15.29.

The mean increased.

15.29 > 14.88

The median would be the middle number of this set.

10, 12, 14, 15, 18, 18, 20

Make sure the numbers are in order from least to greatest.

The middle number of the set is 15.

The median also increased.

15 > 14.5

The mode would be 18. The most frequent number is 18. It appears two times. All the other numbers would appear once.

And the range would be the same, because 12 isn't the greatest nor the smallest number.

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560