Find the mass of a hollow sphere of copper having internal and external diameters of 11.8cm and 12cm respectively ,given the mass of 1c of copper is 8.88g

394.86 grams

Step-by-step explanation:

Volume of the outside shell

r = d/2 = 12 cm/2 = 6cm

V = (4/3) pi * 6^3

V =  4/3 * 3.14 * 216

V = 904.32

Volume of the inside shell

r = d/2 = 11.8/2 = 5.9

V = 4/3 * pi * r^3

V = 4/3 * 3.14 * 5.9^3

V = 859.85

Difference in volume

V_d = 904.32 - 859.85

V_d = 44.47

Mass of sphere

44.47 * 8.88 = 394.86 grams

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x