^^^This is to help you. Please hurry, You will also get 82 points. Can someone please answer these. Find the missing value in the following right triangles:

Note: use your calculator and round all answers to whole numbers

1. a = 4, b=?, c=10

2. a = ?, b=3, c=12

3. a = 6, b=?, c=14

4. a = 7, b=?, c=12

5. a = ?, b=9, c=10

6. a = 3, b=?, c=6

7. a = ?, b = 11, c = 14

8. a = 10, b = ?, c = 12

9. a = 15, b = ?, c = 25

10.a=? , b=12, c=12

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

x = 12

y = 1

for the points!