Michaela runs to the end of her street and back in 90 s. Her brother, Jacob, walks to the end of the street and back in 3 min. They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob. How many times did each person go to the end of the street and back?

Given :

Michaela runs to the end of her street and back in 90 s.

Her brother, Jacob, walks to the end of the street and back in 3 min.

They both run or walk for the same amount of time, but Michaela makes 5 more trips than Jacob.

To Find :

How many times did each person go to the end of the street and back.

Solution :

Let, they both walk for T seconds.

Number of rounds Michaela walk is, n₁ = T/90 .

Number of rounds Jacob walk is, n₂ =T/180 .

It is given that :

n₁ = n₂ + 5

T/90 + T/180 = 5

( T/90 + T/180 ) × 180 = 5×180

2T + T = 900

3T = 900

T = 300 s

So, n₁ = 300/90 = 3

n₂ = 1

Hence, this is the required solution.

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: