A right rectangular prism is packed with cubes of side length 1 over 2 inches. If the prism is packed with 5 cubes along the length, 3 cubes along the width, and 6 cubes along with the height, what is the volume of the prism? A. Fraction 3 and 3 over 4 cubic inches

B.7 cubic inches

C. Fraction 11 and 1 over 4 cubic inches

D.24 cubic inches

C.Fraction 11 and 1 over 4 cubic inches

Step-by-step explanation:

The volume of a rectangular prism of length L, width W, and height H is given by:

V=LWH

The prism is packed with cubes of a side length of a=1/2 inch. The volume of each cube is:

The prism is packed with L=5, W=3, and H=6, thus the volume (in cubes) is:

V=5*3*6=90\ cubes

Since each cube has a volume of :

Expressing as a mixed fraction:

C.Fraction 11 and 1 over 4 cubic inches

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step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.