Give an example of a quadratic function that has two real solutions with a multiplicity of 2.

The equation is;

x^2 + 4x + 4 = 0

Step-by-step explanation:

Here, we want to give a quadratic equation with a real solution that has a multiplicity of two

Generally, there are only two solutions to a quadratic equation since it is a polynomial of degree two

Since we have a multiplicity of 2, it means that the real roots are repeated

Let us have a solution of x = -2

With the multiplicity;

we have x + 2

So let us expand this

(x+2)(x+2)

= x^2 + 4x + 4

The equation is;

x^2 + 4x + 4 = 0

mx+89b(-98)nb

step-by-step explanation:

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step-by-step explanation:

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