The measure of two opposite interior angles of a triangle are and. The exterior angle of the0x−14x+4triangle measures. Solve for the measure of the3x4+5exterior angle.

60 degrees

Step-by-step explanation:

Restructured question:

The measure of two opposite interior angles of a triangle are x−14 and x+4. The exterior angle of the triangle measures 3x-45 . Solve for the measure of the exterior angle.

First you must know that the sum of interior angle of a triangle is equal to the exterior angle

Interior angles = x−14 and x+4

Sum of interior angles = x-14 + x + 4

Sum of interior angles = 2x - 10

Exterior angle = 3x - 45

Equating both:

2x - 10 = 3x - 45

Collect like terms;

2x - 3x = -45 + 10

-x = -35

x = 35

Get the exterior angle:

Exterior angle =   3x - 45

Exterior angle = 3(35) - 45

Exterior angle = 105 - 45

Exterior angle = 60

Hence the measure of the exterior angle is 60 degrees

Note that the functions of the interior and exterior angles are assumed. Same calculation can be employed for any function given

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

step-by-step explanation:

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