What is the equation of the line that passes through the point (-6.-2) and
has a slope of -1/6

y=-1/6x-3

Step-by-step explanation

1 step is substituting, which makes -2=-1/6(-6)+b

2 it become -2=1+b

3 Then subtracting 1 form both sides you get -3=b

4 then put it into slope form making it y=-1/6x-3

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong