Mathematics, 19.12.2020 18:50 sarahidan

Sin(-Q) tan(180+Q)sin(180+Q)sec(270+Q)%sin( 360-Q)cos(270-Q)cosec(180-Q)cot(360 -Q)=tanQ

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Sin(-Q) tan(180+Q)sin(180+Q)sec(270+Q)%sin( 360-Q)cos(270-Q)cosec(180-Q)cot(360 -Q)=tanQ...