Given the arithmetic sequence below, write the general formula in simplified terms and find the 110th term.
-3,2, 7, 12...

542

Step-by-step explanation:

-3, 2, 7, 12

-3 + x = 2 x = 5

2 + x = 7 x = 5

7 + x = 12 x = 5

If you want to find the 3rd term in the sequence and you start with the first number, then you do this:

-3 + (2 * 5) = -3 + (10) = 7

The same goes for the 110th term:

-3 + (109 * 5) = -3 + (545) = 542

The formula to find the nth term is:

f(n) = n(0) + (n-1) * 5

Suppose n(0) = -3 then

f(110) = -3 + {(110-1) * 5}

f(110) = -3 + {(109) * 5}

f(110) = -3 + (545) = 542

You can simplyfy f(n) = n(0) + (n-1) * 5

f(n) = n(0) + (n-1) * 5

f(n) = n(0) + (5n-5)

f(n) = n(0) + 5n - 5

f(110) = -3 + (5 * 110) - 5

f(110) = -3 -5 + (550)

f(110) = - 8 + 550

f(110) = 542

b

step-by-step explanation:

answer: the common difference is -0.10