Solve this please k

↔ sinD × cosD

 ↔ sinC

↔ cosC × tanD

↔ sinD

Step-by-step explanation:

In the given triangle CBD

∵ ∠B is a right angle

∴ CD is the hypotenuse

→ We can use the trigonometry ratios

∵ sinC = opposite side of ∠C ÷ hypotenuse

∴ sinC =

∵ BD = 3 and CD = 5

∴ sinC =

∵ cosC = adjacent side of ∠C ÷ hypotenuse

∴ cosC =

∵ BC = 4 and CD = 5

∴ cosC =

∵ tanC = opposite side of ∠C ÷ adjacent side of ∠C

∴ tanC =

∵ BD = 3 and BC = 4

∴ tanC =

∵ sinD = opposite side of ∠D ÷ hypotenuse

∴ sinD =

∵ BC = 4 and CD = 5

∴ sinD =

∵ cosD = adjacent side of ∠D ÷ hypotenuse

∴ cosD =

∵ BD = 3 and CD = 5

∴ cosD =

∵ tanD = opposite side of ∠D ÷ adjacent side of ∠D

∴ tanD =

∵ BD = 3 and BC = 4

∴ tanD =

Let us find the answer to each tile

→ sinD = ⇒ 4th answer

→ sinC = ⇒ 2nd answer

→ sinD × cosD = ( ) × () = ⇒ 1st answer

→ tanC × tanD = × = 1 ⇒ Not used

→ cosC × tanD = × = ⇒ 3rd answer

47 - 90 = 43

43 - 180 = x

x = 137