Suppose that the radius of the base of a cone is R. Suppose, moreover, that the volume of the cone is the same as the volume of the sphere with radius R (same as the base radius of
the cone). How many times is the height of the cone larger than R?

4

Step-by-step explanation:

1. the volume of the cone is:

where 'h' - the height of the cone, 'π' - 3.1415.

2. the volume of the sphere is:

where 'π' - 3.1415.

3. according to the condition:

4. h=4R means 4 time the height of the cone is larger then R.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

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