The sum of two numbers is 40. One number is 12 more than the other. Find the numbers.

Hello! :)

Let one number be equal to x.

Since the other is 12 more, we can express this as x + 12.

Write an expression showing the sum of these two numbers equal to 40:

x + (x + 12) = 40

Combine like terms:

2x + 12 = 40

Subtract 12 from both sides:

2x = 28

Divide both sides by 2:

x = 14

This is the value of one of the numbers. Since the other number is "x + 12", we can solve for this value:

14 + 12 = 26.

The two numbers are 14 and 26.

-3.396 = -3.4

-0.708 = -0.7

0.304 = 0.3

0.955 = 1

the correct answer is x/3+10≥32

hope this !