Part 2 To train for an upcoming marathon, Susie plans to run 2 miles per day the rst week and then increase the daily distance by a half a mile each
the following weeks. How long before the marathon should she start?
There are many ways to approach this problem. Some include, make a table, write a function, create ordered pairs...
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1. Identify and label the variables.
R. Make a table for up to 6 weeks to see a pattern.
3. Write an equation to represent the nth term of the sequence.
4. If the pattern continues during which week will she run 10 miles per day?
5. Is it reasonable to think that this pattern will continue indenitely, explain?
6. How long before the marathon should she start?

step-by-step explanation:

answer: get jesus in your life

step-by-step explanation:

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt