Hiroshi is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. He begins by assigning coordinates to the vertices of a parallelogram as shown. Which sentence describes what Hiroshi should do to show that the diagonals of the parallelogram bisect each other?

Show that the length of QN¯¯¯¯¯¯ is greater than the length of MP¯¯¯¯¯¯.

Show that MN=QP=a.

Show that the slope of QM¯¯¯¯¯¯ is cb and the slope ofPN¯¯¯¯¯¯ is cb.

Show that the midpoint of MP¯¯¯¯¯¯ is (a+b2, c2) and the midpoint of QN¯¯¯¯¯¯ is (a+b2, c2).
A parallelogram graphed on a coordinate plane. The parallelogram is labeled M N P Q. The vertex labeled as M lies on begin ordered pair b comma c end ordered pair. The vertex labeled as N lies on begin ordered pair a plus b comma c end ordered pair. The vertex labeled as P lies on begin ordered pair a comma 0 end ordered pair. The vertex labeled as Q lies on begin ordered pair 0 comma 0 end ordered pair. Diagonals Q N and M P are drawn.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.

choice b

step-by-step explanation:

f(x) = 88x^2 -264x + 300

the line of symmetry of a parabola is defined by

h = -b/2a

where ax^2 +bx+c=0

so

h = - -264/ (2*88)

h = 3/2

so x = 1.5