find exact value using reference anglescot -53pi/6

cot(-53π/6) = cot(7π/6) = √(3)

Step-by-step explanation:

Remember that a trig function repeats itself every 2π, so you can add any multiple of 2π to your angle and it'll give you the same answer.

cot(-53π/6) = cot(-53π/6 + 2πk)

= cot(-53π/6 + 2π·5)

= cot(-53π/6 + 10π)

= cot(7π/6)

= [-√(3)/2] / [-1/2]

= √(3)

its d but looking at that hurts my eyes frfr

step-by-step explanation: