Please help ;-; -x^3+5x^2+6x=0 solve for x and show work

x = 0, 6, -1

Step-by-step explanation:

To solve for x, first get rid of the negative x^3 by making it positive.

x^3 - 5x^2 - 6x = 0

Now you can start by finding the possible zeros. To do so take the factors of p (in this case the 6 in 6x) and the factors of q (in this case 1 in -x^3) and divide p by q.

P = ±1, ±2, ±3, ±6

Q = 1

possible zeros = ±1, ±2, ±3, ±6

Go through your equation x^3 - 5x^2 - 6x = 0 and check each possible zero until you find one that gets the equation to equal zero.

You could either continue to try each number and the ones that work would be your answer, or you can find one that works, factor it out, then factor your new equation. The second method is faster so that's what I'll use

Check each possible zero. For example:

(1)^3 - 5(1)^2 - 6(1) = 0

-10=0 This will not work

(-1)^3 - 5(-1)^2 - 6(-1) = 0

0 = 0

-1 Works, so now you will factor out -1 using synthetic division.

-1 |            | 1    -5   -6   0

                |      -1     6   0

                 1    -6    0   0

Your new equation is x^2 - 6x = 0

Now factor your new equation:

x(x - 6) = 0

x = 0, 6, -1

I hope this all made sense, have a good day :)

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.