What is the slope of the line represented by the equation 2x+3y= –122x+3y= –12 ?
a.–3/2
b.–2/3
c.2/3
d.3/2

The slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is .

Given that,

2x + 3y = -12

Now here we isolated the variable y

2x + 3y = -12

Now subtract 2x from both sides

3y = -2x - 12

Now divide by 3 in both the sides.

Now

The slope m should be .

Therefore we can conclude that the slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is .

Learn more: link

we have

Isolate variable y

Subtract both sides

Divide by both sides

the slope m is equal to

therefore

the answer is the option B

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source